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FORK()函數(shù)的理解

對(duì)于剛剛接觸Unix/Linux操作系統(tǒng),在Linux下編寫多進(jìn)程的人來(lái)說(shuō),fork是最難理解的概念之一:它執(zhí)行一次卻返回兩個(gè)值。

首先我們來(lái)看下fork函數(shù)的原型:

#i nclude

#i nclude

pid_t fork(void);

返回值:

負(fù)數(shù):如果出錯(cuò),則fork()返回-1,此時(shí)沒有創(chuàng)建新的進(jìn)程。最初的進(jìn)程仍然運(yùn)行。

零:在子進(jìn)程中,fork()返回0

正數(shù):在負(fù)進(jìn)程中,fork()返回正的子進(jìn)程的PID

其次我們來(lái)看下如何利用fork創(chuàng)建子進(jìn)程。

創(chuàng)建子進(jìn)程的樣板代碼如下所示:

pid_t child;

if((child = fork())0)

/*錯(cuò)誤處理*/

else if(child == 0)

/*這是新進(jìn)程*/

else

/*這是最初的父進(jìn)程*/

fock函數(shù)調(diào)用一次卻返回兩次;向父進(jìn)程返回子進(jìn)程的ID,向子進(jìn)程中返回0,

這是因?yàn)楦高M(jìn)程可能存在很多過子進(jìn)程,所以必須通過這個(gè)返回的子進(jìn)程ID來(lái)跟蹤子進(jìn)程,

而子進(jìn)程只有一個(gè)父進(jìn)程,他的ID可以通過getppid取得。

下面我們來(lái)對(duì)比一下兩個(gè)例子:

第一個(gè):

#include

#include

int main()

{

pid_t pid;

int count=0;

pid = fork();

printf( This is first time, pid = %dn, pid );

printf( This is secONd time, pid = %dn, pid );

count++;

printf( count = %dn, count );

if ( pid>0 )

{

printf( This is the parent process,the child has the pid:%dn, pid );

}

else if ( !pid )

{

printf( This is the child Process.n)

}

else

{

printf( fork failed.n );

}

printf( This is third time, pid = %dn, pid );

printf( This is fouth time, pid = %dn, pid );

return 0;

}

運(yùn)行結(jié)果如下:

問題:

這個(gè)結(jié)果很奇怪了,為什么printf的語(yǔ)句執(zhí)行兩次,而那句“count++;”的語(yǔ)句卻只執(zhí)行了一次

接著看:

#include

#include

int main(void)

{

pid_t pid;

int count=0;

pid = fork();

printf( Now, the pid returned by calling fork() is %dn, pid );

if ( pid>0 )

{

printf( This is the parent procESS,the child has the pid:%dn, pid );

printf( In the parent process,count = %dn, count );

}

else if ( !pid )

{

printf( This is the child process.n);

printf( Do your own things here.n );

count ++;

printf( In the child process, count = %dn, count );

}

else

{

printf( fork failed.n );

}

return 0;

}

運(yùn)行結(jié)果如下:

現(xiàn)在來(lái)解釋上面提出的問題。

看這個(gè)程序的時(shí)候,頭腦中必須首先了解一個(gè)概念:在語(yǔ)句pid=fork()之前,只有一個(gè)進(jìn)程在執(zhí)行這段代碼,但在這條語(yǔ)句之后,就變成兩個(gè)進(jìn)程在執(zhí)行了,這兩個(gè)進(jìn)程的代碼部分完全相同,將要執(zhí)行的下一條語(yǔ)句都是if ( pid>0 )……。

兩個(gè)進(jìn)程中,原先就存在的那個(gè)被稱作“父進(jìn)程”,新出現(xiàn)的那個(gè)被稱作“子進(jìn)程”。父子進(jìn)程的區(qū)別除了進(jìn)程標(biāo)志符(process ID)不同外,變量pid的值也不相同,pid存放的是fork的返回值。fork調(diào)用的一個(gè)奇妙之處就是它僅僅被調(diào)用一次,卻能夠返回兩次,它可能有三種不同的返回值:

1. 在父進(jìn)程中,fork返回新創(chuàng)建子進(jìn)程的進(jìn)程ID;

2.在子進(jìn)程中,fork返回0;

3.如果出現(xiàn)錯(cuò)誤,fork返回一個(gè)負(fù)值;

fork出錯(cuò)可能有兩種原因:(1)當(dāng)前的進(jìn)程數(shù)已經(jīng)達(dá)到了系統(tǒng)規(guī)定的上限,這時(shí)errno的值被設(shè)置為EAGAIN。(2)系統(tǒng)內(nèi)存不足,這時(shí)errno的值被設(shè)置為ENOMEM。

接下來(lái)我們來(lái)看看APUE2中對(duì)fork的說(shuō)明:

The new process created by fork is called the child process. This function is called once but returns twice. The only difference in the returns is that the return value in the child is 0, whereas the return value in the parent is the process ID of the new child. The reason the child"s process ID is returned to the parent is that a process can have more than one child, and there is no function that allows a process to o^ain the process IDs of its children. The reason fork returns 0 to the child is that a process can have only a single parent, and the child can always call getppid to o^ain the process ID of its parent. (Process ID 0 is reserved for use by the kernel, so it"s not possible for 0 to be the process ID of a child.)

被fork創(chuàng)建的新進(jìn)程叫做自進(jìn)程。fork函數(shù)被調(diào)用一次,卻兩次返回。返回值唯一的區(qū)別是在子進(jìn)程中返回0,而在父進(jìn)程中返回子進(jìn)程的pid。在父進(jìn)程中要返回子進(jìn)程的pid的原因是父進(jìn)程可能有不止一個(gè)子進(jìn)程,而一個(gè)進(jìn)程又沒有任何函數(shù)可以得到他的子進(jìn)程的pid。

Both the child and the parent continue executing with the instruction that follows the call to fork. The child is a copy of the parent. For example, the child gets a copy of the parent"s data space, heap, and stack. Note that this is a copy for the child; the parent and the child do not share these portions of memory. The parent and the child share the text segment (Section 7.6).

標(biāo)簽: 理解 函數(shù) FORK

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